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golang-使用cast64的坑

package main

import (
    "fmt"
    "github.com/spf13/cast"
)

func main() {
    v := cast.ToInt64("08")
    fmt.Println(" v : ", v)
    v = cast.ToInt64("09")
    fmt.Println(" v1 : ", v)
}

ret: v : 0 v1 : 0

小时转换成整形的时候发现08 和09 获取的结果出错，经过验证和issue中查询发现 如果是0 开头的会考虑进制的问题；因此转化出错； lib对应issue在这里有人提出过： cast.ToInt(“08”) returned 0

得到的回复：

yveshield commented on Jul 7, 2022 The string “08” is not a decimal number, decimal numbers do not have the prefix “0”, nor is it an octal number, octal numbers are only 0-7, nor is it a hexadecimal number, the hexadecimal prefix is “0x “. I don’t think this is a problem with the library, I think it’s important to be aware of this limitation before using the library and avoid it in advance.

The string “08” is not a decimal number, decimal numbers do not have the prefix “0”, nor is it an octal number, octal numbers are only 0-7, nor is it a hexadecimal number, the hexadecimal prefix is “0x “. I don’t think this is a problem with the library, I think it’s important to be aware of this limitation before using the library and avoid it in advance. 字符串“08”不是十进制数，十进制数没有前缀“0”，也不是八进制数，八进制数只有0-7，也不是十六进制数，十六进制前缀是“0x”。我不认为这是lib的问题，我认为在使用lib之前意识到这一限制并提前避免它很重要。

a := []string{“01”, “02”, “03”, “04”, “05”, “06”, “07”, “08”, “09”} for _, v := range a { fmt.Println(cast.ToInt64(v)) } // output 1 2 3 4 5 6 7 0 0 // bug 08 => 0 09 =>0

@gonejack gonejack commented on Sep 20, 2022 This is not a bug — since these leading 0s is treated as octal, or base-8 number system. 这不是一个错误，因为这些前导0被视为八进制或以8为基数的数字系统。

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发表于 2023-03-10 17:03:38。

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